5p^2-980=0

Solution for 5p^2-980=0 equation:

5p^2-980=0

a = 5; b = 0; c = -980;
Δ = b2-4ac
Δ = 02-4·5·(-980)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*5}=\frac{-140}{10}
=-14
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*5}=\frac{140}{10}
=14
$